Can gravitational waves pass through a black hole?
As the title says, what happens when a gravitational wave approaches a black hole? I would presume that something interesting happens because of the way spacetime works near black holes but I have no knowledge to back it up.
What a great question! Do black holes (or indeed other masses) bend gravitational waves?
No, gravitational waves cannot pass through a black hole.
A gravitational wave follows a path through spacetime called a null geodesic. This is the same path that would be followed by a light ray travelling in the same direction, and gravitational waves are affected by black holes in the same way that light rays are. So for example gravitational waves can be refracted by gravitational lenses just as light waves are. And just like light waves, if a gravitational wave crosses the event horizon surrounding a black hole it is then doomed to travel inwards to the singularity and can never escape.
There is one caveat to this. When we talk about a gravitational wave we generally mean a ripple in spacetime that is relatively small. Specifically it is small enough that the energy of the gravitational wave does not significantly affect the spacetime curvature. So when we calculate the trajectory of a gravitational wave near a black hole we take the black hole geometry as fixed, i.e. unaffected by the wave, and we compute the trajectory of the wave in this fixed background.
This is exactly the same approach as we use for calculating the trajectories of light rays. Since light rays carry energy and momentum then, at least in principle, they have their own gravitational fields. But for both the light rays and gravitational waves likely to exist in the universe the energy carried is too small to make a significant contribution to the spacetime curvature.
When you say in your question:
I would presume that something interesting happens because of the way spacetime works near black holes
I would guess you are thinking that the gravitational wave could change the geometry near a black hole, but as described above typical gravitational waves don't have enough energy to do this. It would be reasonable to ask what happens if we give the wave enough energy, but the answer turns out to be that it no longer behaves like a simple wave.
Gravitational waves exist in a regime called linearised gravity where they obey a wave equation that is basically similar to the wave equation light obeys. If we increase the energy so much that gravity becomes non-linear (as if the case for black holes) then the oscillations in the spacetime curvature no longer obey a wave equation and need to be described by the full Einstein equations. For example it has been suggested, but not proven, that really high energy gravitational (or light) waves could interact with each other to form a bound state called a geon. I confess that I'm unsure how much work has been done studying oscillations in this regime.
Excellent answer! If no one else comes along with a better one in the next 24 hours the +20 reputation goes to you!
Just to avoid misinterpretations of the lead sentence, if a train of gravitational waves approaches a black hole, it would also diffract _around_ the hole like a light front does, right? It's not as if there's a GW "shadow" behind the black hole.
@HenningMakholm it depends what you mean by a *shadow*. An observer on the opposite side of a black hole from a GW source would detect GWs, because the GWs would be refracted around the black hole as you describe. However if the observer could see GWs then looking towards the black hole they would indeed see a shadow. That's because the lensing cannot produce a wave vector pointing directly towards the black hole. The wave vectors of the lensed radiation received by the observer would point to a little outside the photon sphere of the black hole.
This is of course why the now famous pictures of Messier 87* show a shadow in the middle. The view in gravitational waves would be similar.
Somewhat oversimplified. The photon ring in M87 is caused by lensing, but is not the same as an Einstein ring. The difference is how close the source of GWs is to the black hole. But yes, there would be a GW "ring" if the source, BH and observer were lined up.
I think you should reorganize your answer. The last section seems to be the most relevant, where you're essentially explaining that *by definition*, a gravitational wave can't have enough energy to impact the spacetime geometry near a black hole. This should be much earlier in the answer. As written, it feels like being jerked around, where you go in one direction, reverse course, and then reverse back in the original direction. Moving the wave definition earlier would prevent this.